log4j - openning a new file  
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ER
PostPosted: 2007-7-1 23:55:00 Top
java-programmer, log4j - openning a new file Hi,

I need to open a new log file in a specific location in the code, how
can I do that?
Log file size and number of records are unknown so I cannot use this
information.

 
timjowers
PostPosted: 2007-7-3 5:31:00 Top
java-programmer >> log4j - openning a new file On Jul 1, 11:54 am, ER <email***@***.com> wrote:
> Hi,
>
> I need to open a new log file in a specific location in the code, how
> can I do that?
> Log file size and number of records are unknown so I cannot use this
> information.

Not sure about log4j but probably the same as Java logging. You can
create a new handler at any time. That handler can be a file handler.
Is something like this waht you need?
FileHandler handler = new FileHandler("another.log",
appendToFile);
Logger logger = Logger.getLogger("examples.LogExample");
logger.addHandler(handler);
Best,
TimJowers

 
Arne Vajh鴍
PostPosted: 2007-8-12 10:23:00 Top
java-programmer >> log4j - openning a new file ER wrote:
> I need to open a new log file in a specific location in the code, how
> can I do that?
> Log file size and number of records are unknown so I cannot use this
> information.

Simple example:

log4j.category.test = debug, logfile
log4j.appender.logfile.threshold = debug
log4j.appender.logfile = org.apache.log4j.FileAppender
log4j.appender.logfile.file = C:/first.log
log4j.appender.logfile.layout = org.apache.log4j.PatternLayout
log4j.appender.logfile.layout.ConversionPattern = %d %C %M %p: %m%n

import org.apache.log4j.*;

public class SwitchFile {
public static void main(String[] args) {
PropertyConfigurator.configure("C:\\log4j.properties");
Logger log = Logger.getLogger("test");
log.info("1");
log.info("2");
FileAppender fa = (FileAppender)log.getAppender("logfile");
fa.setFile("C:/second.log");
fa.activateOptions();
log.info("3");
log.info("4");
}
}

Arne
 
 
 
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